The one-to-one functions g and h are defined as follows. g= {(-6,-3), (0,9), (3,0), (6,4), (7,1)} h(x)= 3x +10 Find the following. g^-1 (0) = ____ h^-1(x)...

The one-to-one functions g and h are defined as follows. g= {(-6,-3), (0,9), (3,0), (6,4), (7,1)} h(x)= 3x +10 Find the following. g^-1 (0) = ____ h^-1(x)...

f^-1(t)= 1/14t-13/14?

for the function Q(X) = 6e0.04(x) does Q-1 exist?

what's the inverse function for this equation Q(x) = 9e0.11x

How do I find the inverse function of f(x)=-(4/x+2)-3

If f(x)=(x+2)/(x+9), then f^-1(-4)=?

I got the domain of [2, inf) but I don't know how to get the inverse with the restricted domain. Please help. An explanation provided will be awesome. Thanks

It Is plotted on a graph

f(x) = (3x) / (x2 + 1). Show that f-1(x) = (6 - 3x2) / (x2 + 2)2

Which of the following expressions is the inverse of the function y = 2x − 6?

sketch the graph of the function that is one-to-one on (+∞,-∞), yet not increasing on (+∞,-∞) and not decreasing on (+∞,-∞)

F(-2)=8 the inverse f-1(8)=A F-1(-9)=-9 the F(-9)=B A=-2 B=-9 Is this correct?

How do you know if you can inverse a word problem function

If f(x)= 2x+3 and g(x)= x^2, Then g[f(-3)] = ?

second dervative of Asin(mx)+Bcos(nx)

This question is from a SAT 2 book. B is the correct answer, and the explanation given is that for the inverse function, two of the points would be (2,1) and (2,5). Since no two points in a function...

I have tried for roughly an hour with no improvement, please help.

Inverse of x^3-4/x

Please guide me through this.

f(x)=4+x/x, g(x)=4/x-1