Evaluate the integral of dt/t√t from 1 to 4

Evaluate the integral of dt/t√t from 1 to 4

Explain why the total area of a region is 25/3 units, but the value of the integral for the same interval is 16/3 units.

The equation of a curve is y=x4+4x+9. (i.) Find the coordinates of the stationary point on the curve and determine its nature. (ii.) Find the area of the region enclosed...

Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = −1

I just need to see how the integral would be set up. From there I ca solve on my own.

Take the above function. If x=1, the velocity is 0 and position is -22. FInd v(t) at any time. Find x(t) at any time. I have no clue how to answer this. Absolutely no...

find the volume generated by revolving the region between them about the x-axis: f(x)=2 and g(x)=cos(x) [0,Pi/2]

Use the Shell Method to compute the volume of the solids obtained by rotating the region enclosed by the graphs of the functions y=x^2, y=8−x^2 and to the right of x=1 about the y-axis.

Use the limit definition to evaluate the definite integral fnInt (2x^3+3)dx lower bound-2 upper bound - 6. (Use right endpoints for c sub-i and equal subintervals

After taking the integral I have (1/7)tan^7x+C-(1/5)tan^5x-C. I got this by breaking a tan^2x off and converting it into sec^2x-1. My question is what happens to my C when I have C-C?

integrate f(t) cos (n*pi*t)/T/2)dt with limit T/2 and 0

I have not been able to sove solve this sum..help me pls

In integration, it is given as: Integration of 1/(1-x^2)^(1/2) = sin^-1 (x) and Integration of 1/(1-x^2)^(1/2) = - cos^-1 (x) Does this...

Find y(x) ?! For dy/dx= a +b(y)+c/x+e(y/x) a,b,c and e are constants

I'm trying to integrate (x)/(d+L-x) respect to x but I get -(d+L)ln(d+L-x) + d + L -x. The correct answer is -(d+L)ln(d+L-x) -x. What I did was to change the variable...

Integration from 0 to π cos6x cos^8x

∫02 [x]nf'(x) dx Please hep me with this integration. It includes an integral part and a derivative :O

Find using substitution: ∫ 1/[x(1+lnx)2] dx I'm not sure what substitution to use.

We have to find the integration of ∫20160 [arctanx]dx the limits are from 0 to 2016 . [.] means greastest integer

0∫ ∏ [sin (n + (1/2) ) X] / sin X dx equals : (2n +1 ) x ∏ / 2 0 ∏ n∏

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