What is the relation between the set of complex numbers, the imaginary numbers, and the real numbers?

What is the relation between the set of complex numbers, the imaginary numbers, and the real numbers?

3x^3+4x^2−7x+2=0 x^4+8x^3+6x^2−5x+14=0 a polynomial has real coefficients. the degree is 4. two zeros are i and 9+i.

Is 3i the fifth root of -243i? Justify please.

8+(x+2y)i=x+2i I need to find the value of x and y, assuming they are both real numbers. How do I go about solving this? Thanks!

(x+yi)4=-7-24I Find x and y In complex numbers

the above is what I got from (4-2i)/(-10+5i) multiplied by (3-i)/(-3+i) written as equation/equation x equation/equation thank you for any help

it is apart of 3i+[1/2]-[1/3](1-3i)+2

Evaluate these powers of i.If there is an imaginary part,be sure to enter your answer in a+bi form,where both a and b are real numbers i1113 i-147

(3i)(6i^2) ( have to simplifiy) Not good with imaginary numbers:( Thanks again

n = 3 -4 and 2i are zeros f(-1) = -45 Find the expanded and simplified polynomial

Hi guys I had a quick question? How do you determine the minimum degree of a function. Do you look at the roots or the extrema in the graph? If you do look at the x intercepts couldn't that answer...

9x^4-28x^2+3=0

wHAT WOULD BE THE ANSWER FOR THIS EQUATION USING SOME RULES OF IMAGINARY NUMBERS. IT WILL BE ALRIGHT IF ANSWER WILL BE IN FRACTION. PLEASE SOLVE AND TELL ME THE ANSWER AND BRIEF DESCRIPTION OF ANSWER...

(2+i)(-3-3i) and ...

the problem 55. i/(3-2i) + 2i/(3+8i) my procedure: (i(3+8i) + 2i(3-2i))/ ((3-2i)(3+8i)) (3i-8+6i+4)/(9+24i-6i+16)...

How would you solve the expressions 2+3i and 2-3i where I is an imaginary number? (i=√-1)

Basically, written out, looks like (a + bi)^6 = 64

Not sure where to go from t^2=-49 I am aware of how to use "i"

when a real number and an imaginary number added together equals 0, does both the real number and the real part of the imaginary number have to equal 0?

It is a problem from my book and I dont know how to do it.

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