(x+yi)4=-7-24I Find x and y In complex numbers

(x+yi)4=-7-24I Find x and y In complex numbers

the above is what I got from (4-2i)/(-10+5i) multiplied by (3-i)/(-3+i) written as equation/equation x equation/equation thank you for any help

part1. Let z=rcisθ where 0<θ<pi. show that Arg(z^2)=2θ. part2. sketch the region defined by {z: Arg(z^2)>pi/2} in the answers it shows region pi/4 to pi/2 and region 5pi/8...

i that right????????

imaginary numbers. complex numbers.radicals. order in a solution

So generally 2 the power of 0 equals 1. same goes for 3 and 4 and so on. You know what I mean. So what is zero in the imaginary dimesion? i is the first of the imaginry numbers, like 1 is in the natural...

Find the indicated power using De Moivre's Theorem. (Express your fully simplified answer in the form a + bi.) ((sqrt)3 - i)^6

What is the relation between the set of complex numbers, the imaginary numbers, and the real numbers?

3x^3+4x^2−7x+2=0 x^4+8x^3+6x^2−5x+14=0 a polynomial has real coefficients. the degree is 4. two zeros are i and 9+i.

Is 3i the fifth root of -243i? Justify please.

8+(x+2y)i=x+2i I need to find the value of x and y, assuming they are both real numbers. How do I go about solving this? Thanks!

Evaluate these powers of i.If there is an imaginary part,be sure to enter your answer in a+bi form,where both a and b are real numbers i1113 i-147

it is apart of 3i+[1/2]-[1/3](1-3i)+2

(3i)(6i^2) ( have to simplifiy) Not good with imaginary numbers:( Thanks again

n = 3 -4 and 2i are zeros f(-1) = -45 Find the expanded and simplified polynomial

wHAT WOULD BE THE ANSWER FOR THIS EQUATION USING SOME RULES OF IMAGINARY NUMBERS. IT WILL BE ALRIGHT IF ANSWER WILL BE IN FRACTION. PLEASE SOLVE AND TELL ME THE ANSWER AND BRIEF DESCRIPTION OF ANSWER...

9x^4-28x^2+3=0

the problem 55. i/(3-2i) + 2i/(3+8i) my procedure: (i(3+8i) + 2i(3-2i))/ ((3-2i)(3+8i)) (3i-8+6i+4)/(9+24i-6i+16)...

(2+i)(-3-3i) and ...

Hi guys I had a quick question? How do you determine the minimum degree of a function. Do you look at the roots or the extrema in the graph? If you do look at the x intercepts couldn't that answer...