(3i)(6i^2) ( have to simplifiy) Not good with imaginary numbers:( Thanks again

(3i)(6i^2) ( have to simplifiy) Not good with imaginary numbers:( Thanks again

n = 3 -4 and 2i are zeros f(-1) = -45 Find the expanded and simplified polynomial

Hi guys I had a quick question? How do you determine the minimum degree of a function. Do you look at the roots or the extrema in the graph? If you do look at the x intercepts couldn't that answer...

wHAT WOULD BE THE ANSWER FOR THIS EQUATION USING SOME RULES OF IMAGINARY NUMBERS. IT WILL BE ALRIGHT IF ANSWER WILL BE IN FRACTION. PLEASE SOLVE AND TELL ME THE ANSWER AND BRIEF DESCRIPTION OF ANSWER...

9x^4-28x^2+3=0

(2+i)(-3-3i) and ...

the problem 55. i/(3-2i) + 2i/(3+8i) my procedure: (i(3+8i) + 2i(3-2i))/ ((3-2i)(3+8i)) (3i-8+6i+4)/(9+24i-6i+16)...

How would you solve the expressions 2+3i and 2-3i where I is an imaginary number? (i=√-1)

Basically, written out, looks like (a + bi)^6 = 64

Not sure where to go from t^2=-49 I am aware of how to use "i"

when a real number and an imaginary number added together equals 0, does both the real number and the real part of the imaginary number have to equal 0?

It is a problem from my book and I dont know how to do it.

I need step by step examples please.

Do you use a different version of FOIL? Do you just multiply 8x4x(-9)? or do you multiply 8iX4i which equals 32 but then mutliply it by -1 because i^2=-1 so you'd have -32, and then multiply...

please help me to solve for the x and y value or help me by telling on hoe to start solving it.

"i" representing the square root of negative 1

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