factor completely if polynomial is prime, state this. -6x^2-27x-27

factor completely if polynomial is prime, state this. -6x^2-27x-27

remember to look first for a common factor and to check by multiplying. If polynomial is prime state this. 5d^2+40d+80

4w-49w^3 if polynomial state this

Factor completely. If Polynomial is prime , state this. -20+31x-12x^2

Factor completely. Remember to look first for a common factor and to check by multiplying. If polynomial is prime, state this. 27m^2-36m+12

1) 3 125x-1 = 2) 2 w-64= 3) 2 y-12y+36+ 6) ...

During the period 1985-2002, the projected enrollment B (in thousands of students) in public schools and the projected enrollment R (in thousands of students) the private school can be modeled by...

how do I factor z2-25 ?

The expression pi(r-3)^2 represents the area covered by the hour hand on a clock in one rotation, where r is the radius of the entire clock. Write a polynomial in standard form that represents the...

what is an equation that describes a problem as a function of the side of the square when the area is 47

2x2-x-6

14) 4 3 2 2y +5y - 12y = 17) ...

what is the answer to factor the following expression: 2a^2-9a-5

Question: The polynomial Q(x) = x^3 - 6x^2 + ax + b has one zero (1 - i√5), where a and b are real. Find the values of a and b and solve the equation for Q(x) = 0. Note that 'i' represents...

QUESTION: Two of the zeros of x4 - 12x3 + 59x2 - 138x + 130 are a+ib and a+2ib. Find a and b and hence, factorise the polynomial over the real field. I assume...

[x-(underroot)5/3]*[x+(underoot)5/3] When this is simplified we get [x^2-5/3] can it be written as 3x^2-5???

Question: The roots of (x-1)(x+i) = 0 are obviously 1, -i. These are not complex conjugates. How do you explain this? Note that 'i' represents the imaginary number i.

a. x^2+2x/x^2-4 b.x^2-5x+4/x^2-1 c. 3x^2-6x/x^2-6x+8 d.x^2+3x-10/x^2-25

how do you factor by complete the square?

Given that the above equation has a double root (two equal roots), it is implied that there is a relationship between the coefficients of x^3 and x, as well as the constant (a, b and c). Note...

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