factorise each of the following expressions completely a) 6x^2y^2-5xy-4 b) 3z-8xyz+4x^2y^2z c) 36y^2-49(x+1)^2

factorise each of the following expressions completely a) 6x^2y^2-5xy-4 b) 3z-8xyz+4x^2y^2z c) 36y^2-49(x+1)^2

3xy+9x-2y-6 howw would i factor by grouping cant figure it out

This question is about factoring polynomials by grouping, and I am confused on how to solve this problem. Hope you will help me as soon as possible.

In problems like 2x^2+3n-9 I keep getting x(x+6)-3(x-3) but don't know if its right or where to go from there.

In problems like 2x^2+3n-9 I keep getting x(x+6)-3(x-3) but don't know if its right or where to go from there

a. x^2+2x/x^2-4 b.x^2-5x+4/x^2-1 c. 3x^2-6x/x^2-6x+8 d.x^2+3x-10/x^2-25

20ay-10ax+42by-21bx

6a^3-10a^2+3a-5

factoring by grouping

3s2-7s-21s+49

How do you complete the factoring 8y^2-6y=2y

The question is 8ax-2a+4bx-b

x3+4x2+x+4 (x3+4x2)+(x+4) x2(x+4)+(x+4) ? x+4 is the common factor but i'm not understanding how to factor out from here.

12a^3-9a^2+4a-3

Could I please just have a brief explanation? Why are you not able to factor the polynomial: 7m + 6mn + 3m^2 + 14n by grouping?

I'm having difficulty understanding this concept and would appreciate help

Are there any quick ways to find two numbers that can both be multiplied and added to reach certain numbers? For example: If I wanted to find a number that multiplied to 14 and added to 9, I...

21x^2-49x+6xy-14y Factor by Grouping Steps...

This is a question from pre algebra, factoring by grouping.

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