20N2 + 47N +24

20N2 + 47N +24

8xy3z2 - 12x3y2z2+20x2y3z3

a^3–a a3–a

a^3–a a3–a

The product of two consecutive odd integers is 1 less than 4 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.

Write as a product x^2–x^4 x2–x4

Write as a product 45b+6a–3ab –90 Write as a product45b+6a–3ab –90

Write as a product a^3–a a3–a

Write as a product ab^2 –a–b^3+b Write as a productab2 –a–b3+b

Write as a product bx^2 +2b^2–b3–2x^2 Write as a productbx2 +2b2–b3–2x2

Please show step by step how to factor completely.

I want to know how to factor the equation using the box method/unfoil method thank you

Factor 49x^2–(y+8x)^2 Factor49x2–(y+8x)2

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factor the expression completely

the expression must be factored completely

We have to find factored form then multiply the factors.

I don't know how to solve using factoring

X2-81 12(x-9) and (x-9)2, are both acceptable?

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