Factoring trinomial. Don't know where to start pls help thanks.

Factoring trinomial. Don't know where to start pls help thanks.

I need to factor (x^+y^)(x^3+y^3) to get a polynomial that contains Only x+y and xy. Is this possible?

I really need the full answer ASAP with the solution n stuff...Very much appreciated

Here are 2 examples of the problems I am struggling with: 16(11x-13)^2 - 25(2x+7)^2 (2x+3)^7(5x-1)^30(8x+1)^3 - (2x+3)^5(5x-1)^30(8x+1)^5

a) Factor p(x) b) Use the factored form to find the zeros of p(x)

Just need to see the steps in factoring this

(x^2+1)^5(4x)-x^2(7)(x^2+1)^4(4x)/(x^2+1)^9

I need help with this ASAP

Is 16x^4-81x^2 a perfect square trinomial or a difference of square

The answer that I got was t(3t^2 + 2) / 2 but the answer stated was t((3/2)t^2 + 1).

Determine the value/s of k to make the trinomial factorable a.) x(squared)+5x+k b.) 32a(squared)-ka-5 c.) 6m(squared)-17+k

Am I able to do this? 1=(a)log(4)+(a)log(2) 1=a(log(4)+log(2)) 1=a(log(8)) a=1/log(8)

How do you factor (n(t) - dn(t)) + b(n(t) - dn(t)) to become (1+b)(1-d)n(t) ?

a^3–a a3–a

factor -81y as far as possible please.

i need to figure out in equation form starting at 6,3

How would you factor y = -3x2 - 18x -20? With your answer, what would your x values be when y = 0? Show your steps. Explain why your x values have 2 answers.

can anyone help me with this?

In class our professor turned: (3n)*5 + (1/2) * 2(3n-1) into 3n(6) - 1 How is this possible and what steps were used to make this happen? Thanks a bunch!

If you could help me solve this question that would be great! Thank you!