a^3–a a3–a

a^3–a a3–a

a^3–a a3–a

I want to know how to factor the equation using the box method/unfoil method thank you

x2 +11x +30

The product of two consecutive odd integers is 1 less than 4 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.

20N2 + 47N +24

16x2 - 16x-12

2x2y +4xy+6xy2

Please show step by step how to factor completely.

10a2-5a-15

8xy3z2 - 12x3y2z2+20x2y3z3

Factor the polynomial completely x^4 - 40^2 + 39

We have to find factored form then multiply the factors.

Write as a product bx^2 +2b^2–b3–2x^2 Write as a productbx2 +2b2–b3–2x2

I don't know how to solve using factoring

Factor 49x^2–(y+8x)^2 Factor49x2–(y+8x)2

Factor (5a–3b)^2–25a^2 Factor(5a–3b)2–25a2

factor (−2a^2+3b)^2–4a^4 (−2a2+3b)2–4a4

factor the expression completely

the expression must be factored completely

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