helppppppppppppppppppppppppppppppppp

helppppppppppppppppppppppppppppppppp

Length of major axis: 26, foci on x-axis, ellipse passes through the point square root 13, 6,centered at the origin

I just need the equation

Find the points of tangency given f(x) = 15/2/x is tangent to x2/25 + y2/9 = 1

graph x2/25 + y2/9 = 1

ellipse topic

A road passes through a tunnel in the form of a semi-ellipse. In order to widen the road to accomodate more traffic,engineers must design a larger tunnel that is twice as wide and 1.5 times as tall...

The arch of a bridge is a semi ellipse with a horizontal major axis. The span is 30ft and the top of the arch is 10ft above the major axis. The roadway is horizontal and is 2ft above the top of the...

Find an equation for the ellipse that satisfies the given conditions: Foci (1, ±4) Vertices (1, ±7)

change this equation in standard form by completing the square.

a. Foci (±4 , 2), major axis 10. B. Major axis parallel to x-axis, center (- 3 , 1), one end of the vertices at (- 5 , 1) and the length of latus rectum is 1. C Ends of major axis...

A planet has an elliptical orbit around a sun, (one of the foci of the ellipse. The planet is 1,325,022 miles from the sun at its furthest point. If the sun is 231,000 miles from the center of the...

Pls let me know about the value of e=1/2?

please solve for y for this ellipse problem!

Reduce the equation 32𝑥2 + 50𝑦2 − 128𝑥 − 672 = 0 to standard form. Locate the center, foci, vertices, ends of latera recta, and trace the curve.

5𝑥2 + 2𝑦2 = 100

Find the coordinates of the foci, ends of major and minor axes, ends of the latus rectum 5𝑥^2 + 2𝑦^2 = 100

a. Center (0 , 0), one vertex (0 , - 7), one end minor axis (5 , 0). b. Foci (±3 , 0), vertices (±5 , 0). c. Foci (±4 , 2), major axis 10. d. Major axis parallel to x-axis, center...

find the area of the ellipse (x+2y)2 + (3x+4y)2 =1

I have to find the vertices, foci, and both axes lengths. I can do all this but I don't understand what to do with 36x^2 + 25y^2 without affecting the 1 on the right side of the...