OABC is a rectangle where A lies on x-axis, C lies on y-axis and B lies on the curve x2/3 + y2/3 = a2/3 , O is the origin. Find the coordinates of B so that the area of OABC is maximum...

OABC is a rectangle where A lies on x-axis, C lies on y-axis and B lies on the curve x2/3 + y2/3 = a2/3 , O is the origin. Find the coordinates of B so that the area of OABC is maximum...

OABC is a rectangle where A lies on x-axis, C lies on y-axis and B lies on the curve x 2 3 + y 2 3 = a 2 3 , O is the origin. Find the coordinates of B so that the area of OABC is maximum...

A curve has equation y=(x2+1)4+2(x2+1)3. Show that dy/dx=4x(x2+1)2 (2x2+5) and hence show that the curve has one stationary (critical) point. State the coordinates of the stationary...

Find the set of values for k for which the line y=2x−k meets the curve y=x2+kx−2 at two distinct points. I only know you have to use a discriminant. :/

Hi all, I wish to draw a cubic curve that has a Y intersact at 37, the downward slope and reach minimum point of 27.1, then upward slope and reach maximum point at 40.8, then finally...

if you calculate the area under the curve f(x)=x2 from x=0 to x=5 using a left had rectangular approximation, a right hand approximation, and a midpoint rectangular approximation, in each case...

Find the area under the standard normal curve which lies a.) to the left of 0.47 b.) to the right of z=-0.06 c.) to the right of z=2.53 d.) to the left of z=-1.31 e.) between z= 0.72 and z=1.59 f...

the might be the most confusing question for me, in my opinion.

12th grade advanced functions math

Find the equation of the tangent line to the curve at the given point.\\ y=1+2x-x3, (1,2) y=

The point P(9,7) lies on the curve y= √x +4. Let Q be the point (x,√x+4) if x is 9.1, the slope of PQ is 0.166206 if x= 9.01, the slope of PQ is 0.16662 if x= 8.9, the slope...

Find the curvature of the curve of intersection of the cylinder x^2+y^2=16 and the plane x+z=5 at (4, 0, 1).

Find the curvature of the curve r(t)=(t+1)i+2(t^2-1)j+(t-2)k. r'(t)=i+4tj+k sqrt(1^2+(4t)^2+1^2)=sqrt(2+16t^2) r''(t)=4j r'(t)xr''(t)=? Please show...