4√2(¡-1)

4√2(¡-1)

Write in standard notation, : a+bi 2(cos π/3+ isin π/3)

Evaluate Z ∫C(z^2 - z)/(2z + 1) dz where C is: (i) the unit circle in the counterclockwise direction; (ii) the circle |z − 2| = 1 in the counterclockwise direction. Do I use...

You are given four complex numbers in rectangular form: p=5+3j. q=2-4j. r=6j. s=-3-2j. Simplify the expressions below giving the answer in rectangular form: (i) p+s (ii)...

Find the nth roots of the complex number for the specified value of n: -17i, n=6

For some reason 1+i = root 2 * e ^ pi / 4 which i dont understand how so I would like an explanation for this...

please help I have no idea what this means and I need the work to show how to do it

Here no plus or minus is there, then how could we able to find conjugate?

Find the nth roots of the complex number for the specified value of n. 2-2i, n=4

Consider complex numbers Za=1+i and Zb=u+vi where u<0<v. If S represents the area bounded by the origin, Za and Zb, find Arg(Zb) for which real(Zb) + Imag(Zb) = (2/root3)S

Find the fifth roots of the complex number: cos(5pi/4)+isin(5pi/4)

A. Calculate the perimeter of the polygon whose vertices are the complex fourth roots of 1. B. Calculate the perimeter of the polygon whose vertices are the complex ninth roots of 1....

I'd greatly appreciate your help. Thank you for your time.

(12(cos 420 + i sin 420)) / (2(cos 120 + i sin 120)) Thank you for your time.

imaginary numbers. complex numbers.radicals. order in a solution

Given that: z=tan(α)+i, where 0<α<(1/2)*pi Find the absolute value of z in its simplest form. How the hell do I solve this?

How do you put the complex number -2+i into a form of e^{ix} ? with i = sqrt(-1) x= angle...

if y=x²+x-4, evaluate y given x=2i. this is the first time I have seen this so I am unsure how to proceed.

Use an algebraic method to find the cube roots of the complex number: 5(cos(π/6)+isin(π /6)) The answer needs to be in a+bi form.

(-1+2i)(-5+3i) having trouble on this one, please show me step by step and the answer. Thank you so much. I appreciate it