How do you put the complex number -2+i into a form of e^{ix} ? with i = sqrt(-1) x= angle...

How do you put the complex number -2+i into a form of e^{ix} ? with i = sqrt(-1) x= angle...

az²+bz+10i=0 where a and b are real, has a root of 3-i. Show that a=3 and find the value. I know that 3+i is also a root and I would be able to find the value of b if I could...

If X=a+b+c Y= am+bn+c Z=an+bm+c where n and m are complex root of unity then XYZ equal to ?

What are the of the worked out complex roots?

the radius of convergence of the power series ∑∞(n +2i) zn is n=0 please sir help me please irequest you

Write the complex number z=-1+√2i in polar form. Express the argument theta in degrees, with 0°≤theta<360°. Please show step by step work to solution and provide final answer...

if w= u(x,y) +i v(x,y) is analytic function of z=x+i y , then dw/dz equals a) i ∂w/∂x b) -i ∂w/∂x ...

if origin and 2-i are two vertices of an equilateral triangle then determine third vertex.

If x/(4+yi) +1/2i = 1 , what is the value of x and y ?