x^2+2x-5=0

x^2+2x-5=0

please answer it I m stuck in this question.

change this equation in standard form by completing the square.

y=2+cx+d the turning point is (3,7) work out the values of c and d

Solve the equation by completing the square. state whether the solutions are real or non-real. 3x^2+2x+1=0 I solved and got (−1+√2i)/3,(−1-√2i)/3 I am not sure...

Need help finding out howto get rid of 9 and 79 can't be divided by 9

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Is it possible to complete the square for this equation ? : y^2+x^2=2x

I know the answer is x=5 or x=-12. but could you show me how to work it out. than you. solve this equation by completing the square.

7a2 +14a + 86 = 9

Completing the square - Vertex is (-5/4, 11/16) Quadratic Formula (-5/4, 11/8) This is what I got when I used both of the formulas. I am pretty sure that you are supposed to...

f(x)=-3x2-2+1 I tried it and I got (-3x2-2x+1)-6 after completing the square, then I factored it and got (-3x+1)(x+1)-6 , if I did it correctly how am I supposed to get a vertex...

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The area of the room is 176 square feet and is five feet longer than its wide.

Rewrite the quadratic function in standard form by completing the square f(x)= -1/4x^2+5x-2

what equation results from completing the square and then factoring? x^2+4x=5

show me the steps please