Currently looking to the answer to this question for extra credit. Any help would be greatly appreciated!

Currently looking to the answer to this question for extra credit. Any help would be greatly appreciated!

solve x^2-6x=-10 by completing the square

x^2+2x-5=0

please answer it I m stuck in this question.

change this equation in standard form by completing the square.

y=2+cx+d the turning point is (3,7) work out the values of c and d

Solve the equation by completing the square. state whether the solutions are real or non-real. 3x^2+2x+1=0 I solved and got (−1+√2i)/3,(−1-√2i)/3 I am not sure...

Need help finding out howto get rid of 9 and 79 can't be divided by 9

i also have the equation x^2+11x+c. i have no clue what to do to make each trinomial a perfect square

Sean and Mason run out of gas while fishing from their boat in the bay. they set off an emergency flare with an vertical velocity of 30 meters per second. The height of the flats in meters can be...

An athletic field with perimeter of 40km consists of a rectangle with a semicircle at each end. Find Dimensions that yield greatest possible Area by completing the square for the rectangular region...

I know the answer is x=5 or x=-12. but could you show me how to work it out. than you. solve this equation by completing the square.

Is it possible to complete the square for this equation ? : y^2+x^2=2x

7a2 +14a + 86 = 9

Completing the square - Vertex is (-5/4, 11/16) Quadratic Formula (-5/4, 11/8) This is what I got when I used both of the formulas. I am pretty sure that you are supposed to...

f(x)=-3x2-2+1 I tried it and I got (-3x2-2x+1)-6 after completing the square, then I factored it and got (-3x+1)(x+1)-6 , if I did it correctly how am I supposed to get a vertex...

How do you solve this problem by completing the square? x^2+6x=9

-Completing the square - Round final answer to hundredths place

Rewrite the quadratic function in standard form by completing the square f(x)= -1/4x^2+5x-2

The area of the room is 176 square feet and is five feet longer than its wide.