You must find the volume of the gas after she moved it outdoors. Remember volume at room temperature measures in STP... 273Kelvin...

You must find the volume of the gas after she moved it outdoors. Remember volume at room temperature measures in STP... 273Kelvin...

I need help please

Hi. In year 13 Chemistry we titrated an iodine solution with freshly squeezed orange juice which had been stored at different temperatures. We keep the orange juice solution in an incubator to...

What is the final volume of 195 mL of oxygen gas at 14.0 deg C if the gas is heated to 211 deg C? Assume the pressure and the amount of gas are held constant. How do I work this out?

Investigation 1)In the glass beaker measure out 20 ml of water. 2)Using the measuring scale weigh and calculate the mass of the non solution reaction vessel. 3)Add 1ml of the cyclohexanol...

this question comes from a take home exam that is due tomorrow. i don't know what i should do to solve this problem, i don't understand

please help me i am unable to get the solution

I really need to solve this so I can learn how the steps go for it.

im not exactly sure how to find the molarity, an answer would be nice, and also how to do it.

Chemistry Help please!

(0.050 cm3) * ? = ? m3

Aluminium reacts with HCl to form aluminium chloride and hydrogen gas. The equation is shown below: 2Al + 6HCl —-> 2AlCl3 + 3H2 what volume of hydrogen is...

i need to solve the word problem with that in info and : 3CaCO3 + 2FePO4 = 1Ca3(PO4)2 + 1Fe2(CO3)3

please help!!!

Assume a full pill weighs 300 mg and contains 27.0 mg of Fe. What is the % recovery for your experiment? In other words, what percentage of the total Fe in the pill did you recover?

need help solving equations

Please answer my chemistry word problem. Basically, just do conversions for me.

can you help me answer this

Both processes are known to be second-order in reactant, and k1 is known to be .270 L/mol(s) at 25 C. In a particular experiment, A and B were placed into separate containers at 25 C,where [A]o =...

8.20x10^-2 x 2.50x10^6