Graph the following function. g(x) = 2e^x+1 +4 To draw the graph, plot two point and the asymptotes. I did find out that the...

Graph the following function. g(x) = 2e^x+1 +4 To draw the graph, plot two point and the asymptotes. I did find out that the...

a) r(x) = x − 2 / x2 − 4x b) s(x) = x2 − 2x + 1 / x3 − 3x2

find all horizontal and vertical asymptotes of y=x/sinx vertical asymptotes: if i set denominator to 0, then sinx=0 and x= 0 or npi? horizontal asymptotes:...

For f(x)=5 (x+2)(2x-1)/ (4-x)(3x+2) The horizontal asymptote is at y = The vertical asymptote(s) is/are at =

identify the asymptotes in the equation, h(x) = 4 sec( π/ 4 (x + 1)).Enter your answers as a comma-separated list of equations

Identify the asymptotes in the graph f(x) = −5 cot(2x),(Enter your answers as a comma-separated list of equations.)

identify the asymptotes of j(x) = tan(π/4x) (enter your answers as a comma-separated list of equations.)

Find an equation for the hyperbola that satisfies the given conditions: Foci (0,±6), asymptotes y=±(1/3)x

(x+1)2 - (y-3)2 =1 9. 16. Find the center , foci,vertices, and asymptotes of the hyperbola

1/7*3x

Find the vertical and horizontal asymptotes of the hyperbola y= (x-2)/(x-4) and hence sketch the graph.

Find a function that represents a graph that has a vertical asymptote at x=5 and a hole at x=-3 The answer is: k(x)= (x2+2x-3)/(x2-2x-15) I dont understand...

create a rational function with a slant asymptote of y=x+8 And vertical asymptotes x=2 and x=-1

3 f(x) = ______ +1 x + 2

a) find the equations of the vertical and horizontal asymptotes of the graph of f. the vertical and horizontal asymptotes to the graph of f intersect at the point Q(1,3) b) find...

Design and Analysis of Algorithms

Asymptotes: Under certain laboratory conditions, an agar plate contains ?(??) = 400(3 − ? −??) bacteria t hours after the start of the experiment. (15 points) a. How many bacteria...

f(x)=3/(x+2)+1

What is the equation of the asymptotes for the function y=2tan(3x)

Y Intercept ordered pair is (0,5)