sec is 1/cos, so when you multiply them together do they cancel out and leave a quadratic equation for theta? (4theta + 8) x (6theta +2) = 1 ?

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sec is 1/cos, so when you multiply them together do they cancel out and leave a quadratic equation for theta? (4theta + 8) x (6theta +2) = 1 ?

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y=5/7x-3 y=-7/6x+6 -5/x+-7/4=-3 7/x+-6/y=6 x2=-3y y2=6x -5x-7=-3 7x-6y=6 -5x-7y-3=7xy+6

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