you have a total perimeter 72inches for a rectangle

set up your perimeter equation for a rectangle = 72

2(width)+2(length)= 72

your length is 12 inches longer than width; we will want to try to use one variable. Let's use w for width!

2w + 2(w+12)=72

distribute the 2 and combine like terms

4w+24 = 72

subtract 24 from each side

4w=48

divide by 4 to find that width (w) = 12.... now, use the original length equation we used to solve for w before (remember; length = w + 12)

12 + 12 = 24;

**Your rectangle's width is 12 and the length is 24.** If you'd like to check your work, which I always suggest, just use the formula for the perimeter of a rectangle; where width (W) = 12 and length (L) = 24

Perimeter is the sum of all sides

24+24+12+12=72

or

Perimeter of a rectangle is 2(w)+2(L); where w is width and L is length

2(24) + 2 (12) = 72