
Mark M. answered 02/16/22
Mathematics Teacher - NCLB Highly Qualified
a5 = a1 + 4d
-16 = a1 + (4)(-5)
-16 = a1 - 20
4 = a1
an = 4 + (n - 1)(-5)
Chloe E.
asked 02/16/22I put a5 but I meant a5 lol I didn't know how to type it
Mark M. answered 02/16/22
Mathematics Teacher - NCLB Highly Qualified
a5 = a1 + 4d
-16 = a1 + (4)(-5)
-16 = a1 - 20
4 = a1
an = 4 + (n - 1)(-5)
Stanton D. answered 02/16/22
Tutor to Pique Your Sciences Interest
Hi Chloë E.,4
I suppose you have an arithmetic sequence? Just count backwards to a0 I think you want? That's 5 terms back = 5*(-(-5)) = 25. So a0 = -16+25 = 9. Let's check: a1 = 9-5 = 4; a2 = 4-5 = -1; a3 = -1-5 = -6; a4 = -6-5 = -11; a5 = -11-5 = -16. Yup!
If your course likes to number its sequences from a1 instead, you have that in the list also. Personally I always thought a0 made sense, but that's the computer geek in me.
By the way Chloë, if you can't get a symbol, just state what it does, and put the "argument" in parentheses, like this: asub(0) . For exponents, the universal text symbol is "^", so 24 = 2^(4), for example.
-- Cheers, --Mr. d.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Mark M.
The convention in mathematics is that the first term of a sequence/series arithmetic or geometric is a sub 1.02/16/22