Use process of optimization
Do you mean f(x) = e^{-x} sin(2x)?
f'(x) = e^{-x} (2cos(2x) - sin(2x))
Solve f'(x) = 0 for extreme values,
tan(2x) = 1/2
x = .2318 rad , f(.2318) = .3547 <==Answer
Use process of optimization
Do you mean f(x) = e^{-x} sin(2x)?
f'(x) = e^{-x} (2cos(2x) - sin(2x))
Solve f'(x) = 0 for extreme values,
tan(2x) = 1/2
x = .2318 rad , f(.2318) = .3547 <==Answer
The way they write equations and formulas sometimes is incorrect. You can write the same function in the way as Robert J. did, or as f(x) = exp(-xsin2x). If the exp(-x) is to be multiplied by sin(2x) then it is to be included in parenthesis, such as f(x) = exp(-x) sin(2x) , which is a totally different function. If we take
f(x) = exp( -xsin(2x)) then f'(x) = 0 if tan(2x) =-2x. This equation can be satisfied if x = 0 which is visible
without differentiation. If f(x) = exp(-x) sin (2x) then f'(x) = exp(-x)(2cos(2x) -sin(2x)) = 0 or
tan(2x) = 2 x = (1/2) atan(2) (cos(2x) = 1 and can be a divisor)
Because tan (2x) is a periodic function with the period = pi, we can write more common solution in the following way: x = (1/2)(atan(2x) +(or -) pin)
Comments
it is e minus x
Thank you so much, Robert! Can you, please, also show how did you find x.