A parallel line will have the same slope as the given line. To find the slope of the given line, put -3y = -6x + 1 into y-intercept form:
y = mx + b, where m is the slope and b is the y-intercept
We can now use the slope you just found, m, to find the equation for a line the passes through the point (9, 0). For this, we use point-intercept form:
y + y1 = m(x + x1), where y1 is the point's y-value and x1 is its x-value
After plugging in for m, y1, and x1, solve by again translating the equation to y-intercept form.
Hope this helps!