Mark M. answered 02/11/15
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Retired math prof. Very extensive Precalculus tutoring experience.
Value in one year = 27600 - 0.10(27600)=27600(1-0.10)
= 27600(0.90)
Value in 2 years = 27600(0.90) - 0.10(27600)(0.90)
= 27600(0.90)(1 - 0.10)
= 27600(0.90)2
Value in n years = 27600(0.90)n
27600(0.90)n = 13800
(0.90)n = 0.5
log(0.90)n = log(0.5)
nlog(0.90) = log(0.5) So, n = log(0.5)/log(0.90)
n = 6.5788 years
The car will be worth half of its original value in about
6.6 years.