1. What is the focal length of a mirror that has a radius of curvature of 0.09 m?
For a Convex mirror f = - R / 2 = - 0.045 m. For a Concave mirror f = + 0.045 m.
2. A converging lens has a focal length of 0.36 m. If an object is placed at 0.64 m from the lens, where will its image be located?
The lens formula is 1 / U + 1 / V = 1 / f where f is the lens focal length, u is the distance of the object to the lens and v is the image distance from the lens.
1 / 0.64 + 1 / V = 1/ 0.36
1 / V = 100 /36 - 100 / 64 = 2.78 - 1.55 = 1.22 = 1 / V
v = 0.82 m to the right of the lens
3. Is the image virtual or real in the previous question?
The image can be projected onto a screen. It is inverted and it is a real image.