A man flies a small airplane from Fargo to Bismarck, North Dakota
A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour and 12 minutes. What is the plane's speed in still air, and how fast is the wind blowing?
his plane speed equals mph?
the wind speed equals mph?
First, convert the time of the second flight to hours. 1 hour 12 min = 1.2 hours.
The plane's ground speed from Fargo to Bismarck is 180 / 2 = 90 mph, and the plane's ground speed on the return trip is 180 / 1.2 = 150 mph. From these figures, we can determine that the plane's ground speed in still air is (150 + 90) / 2 = 120 mph, and the wind speed is (150 - 90) / 2 = 30 mph. Assume the direction of the wind has not changed.