HOw would I factor this out?
In addition to John's work:
(x^{2} + 9) is always positive, thus we have to find solution for x + 1 < 0 ---> x < -1
Interval (-∞, -1) is the solution for given inequality.
HOw would I factor this out?
In addition to John's work:
(x^{2} + 9) is always positive, thus we have to find solution for x + 1 < 0 ---> x < -1
Interval (-∞, -1) is the solution for given inequality.
Begin by separating the factors into two groups:
(x^{3} + x^{2}) + (9x + 9) < 0
Factor out the GCF in each parenthesis
x^{2}(x + 1) + 9(x + 1) <0
Since factor in parenthesis is the same, we can combine the GCF's into their own factor
(x^{2} + 9)(x + 1) < 0