HOw would I factor this out?

In addition to John's work:

(x^{2} + 9) is always positive, thus we have to find solution for x + 1 < 0 ---> x < -1

Interval **(-∞, -1)** is the solution for given inequality.

HOw would I factor this out?

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(x^{2} + 9) is always positive, thus we have to find solution for x + 1 < 0 ---> x < -1

Interval **(-∞, -1)** is the solution for given inequality.

Begin by separating the factors into two groups:

(x^{3} + x^{2}) + (9x + 9) < 0

Factor out the GCF in each parenthesis

x^{2}(x + 1) + 9(x + 1) <0

Since factor in parenthesis is the same, we can combine the GCF's into their own factor

(x^{2} + 9)(x + 1) < 0

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