
Carol H. answered 10/28/14
Tutor
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Experienced Mathematics Tutor w/ Master's Degree in Math
x2(2-5/x+2/x2)>0(x2)
2x2-5x+2>0
(2x-1)(x-2)>0 Equation A
2x-1 = 0 or x-2 = 0
2x = 1 or x = 2
x = 1/2 or x = 2
Set up a table in the following way:
(-∞,1/2) (1/2, 2) (2,∞)
Now choose a number between -∞ and 1/2
Let's choose x = 0 and substitute that into Equation A
(2(0)-1)(0-2)= (-1)(-2)=2 You only care that it is a positive number
Place a plus sign under (-∞,1/2) on your table.
Next, choose a number between 1/2 and 2.
Let's choose x = 1 and substitute that into Equation A
(2(1)-1)(1-2)=(1)(-1)=-1 Again you only care that it is a negative number
Last, choose a number between 2 and ∞
Let's choose x = 4 and substitute into Equation A
(2(4)-1)(4-2)=(7)(2)=14. So, your answer is positive.
Now your table looks like this:
(-∞,1/2) (1/2, 2) (2,∞)
+ - +
Since your original has a > sign, you only want those positive results.
Answer: (-∞,1/2) U (2,∞)