d = rt, so t = d/r

The times are equal.

Let r be the rate of the slower car.

320/(r + 10) = 240/r

Cross multiply.

320r = 240(r + 10)

320r = 240r + 2400

80r = 2400

r = 30 mph

30 + 10 = 40 mph

Yoai L.

asked • 09/30/18One car travels 10km an hour faster than a second car. The first car travels 320km in the same time that the second car travels 240km. Please help me find the rate of each car.

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d = rt, so t = d/r

The times are equal.

Let r be the rate of the slower car.

320/(r + 10) = 240/r

Cross multiply.

320r = 240(r + 10)

320r = 240r + 2400

80r = 2400

r = 30 mph

30 + 10 = 40 mph

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