
Jay T. answered 09/20/18
Tutor
New to Wyzant
Effective Math Tutor
Let V be the speed of the faster train and V-19 be the speed of the slower train. Then, because the two trains are heading directly at each other, their relative speed with respect to each other is:
V + (V-19) = 2V-19.
Distance covered by the two after 5 hours, is
5 * (2V-19) = 10V-95
That distance is the sum of the distances each of the trains traveled which is 825 miles since the have met. Therefore,
10V - 95 = 825
10V = 920
V = 92 (Faster train)
V – 19 = 73 (Slower train)
V + (V-19) = 2V-19.
Distance covered by the two after 5 hours, is
5 * (2V-19) = 10V-95
That distance is the sum of the distances each of the trains traveled which is 825 miles since the have met. Therefore,
10V - 95 = 825
10V = 920
V = 92 (Faster train)
V – 19 = 73 (Slower train)