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The sum of three numbers is 83. The second number is 4 more than the first number. The third number is 5 less than twice the first number. Find the three number

I see where this is like the one before but we are having trouble trying to figure out where to put the 5 less than2 x the first number.

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Nathan B. | Elementary and Algebraic skilledElementary and Algebraic skilled
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Here's what we know
a + b + c = 83 (sum of three numbers is 83)
b = a + 4 (the second number is 4 more than the first)
c = 2a - 5 (the third is 5 less than twice the first)
 
We have variable values, so let's plug them in:
a + a + 4 + 2a - 5 = 83
simplify
4a - 1 = 83
Add 1 to both sides:
4a = 84
Divide by 4:
a = 21
 
And now that we know a, you can find b and c.