The answer is 15, but I don't know how to get to that answer.

For this question it's useful to define the unknown. Let's call x the number of liters of 12% acid solution to be used.

Since we're going to mix the solutions, our new solution will have **(x+5)** liters.

How much acid is present in the new solution? Well, the original 5 liters contribute 20%, that is

20*5/100 = 1 liter of acid

The added solution contributes 12%, that is

12*x/100 = 0.12*x liters

So we have a total of 1 + 0.12*x liters of acid in the **(x+5)** liters of solution (see above) and we want the acid to be
**14%** so:

1 + 0.12*x =** 14***(x+5)/100

and now we just need to solve for x:

1 + 0.12*x = 0.14*(x+5)

1 + 0.12*x = 0.14*x + 0.7

1 - 0.7 = 0.14*x - 0.12*x

0.3 = 0.02*x

30 = 2*x

15 = x

And that's the correct answer!

## Comments

Thank you so much! :)