
Arturo O. answered 09/02/18
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I assume you mean
h(x) = [√(x2 + 9)]3
There is more than one way to get h(x) from composing 2 functions. Here is one:
g(x) = √(x2 + 9)
Let f(x) = x3
f(g(x)) = [√(x2 + 9)]3
Here is another:
You can express h(x) as
h(x) = (x2 + 9)3/2 = √[(x2 + 9)3]
g(x) = (x2 + 9)3
f(x) = √x
f(g(x)) = √[(x2 + 9)3]