for 3 consecutive integers , the sum of the first and third integer is 12 more than 3 times the second integer. what is the third integer?

Question

Hi stuck on this problem for a long time but cannot solve it!

Answer 1

The 3 consecutive integers are

 

n

n + 1

n + 2

 

The wording of the problem translates into

 

n + (n + 2) = 3(n + 1) + 12

 

Solve for n, get n + 2, and finish from here.