Find the score that is 1/2 standard deviation above the mean. Mean is 70 and standard deviation is 14.

Question

Scores on a test are normally distributed with a mean of 70 and standard deviation of 14.  

Answer 1

Use the formula for the z-score:

 

z = (x-μ)/σ

• z = z-score = 1/2
• x = the score that is 1/2 of a standard deviation above the mean
• μ = mean = 70
• σ = standard deviation = 14

 

z = (x-μ)/σ

(1/2) = (x-70)/14

 

Solve for x.