Zoe C.

asked • 06/30/18# what is the general equation for (0,0) with the radius of 5

x

^{2}-y^{2}=5
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## 1 Expert Answer

Philip P. answered • 06/30/18

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The standard form for a circle of radius r and center at (h,k) is:

(x-h)

^{2}+ (y-k)^{2}= r^{2}In your case, (h,k) = (0,0) and r = 5, so:

x

^{2}+ y^{2}= 5^{2}x

^{2}+ y^{2}= 25The general form of a circle is:

x

^{2}+ y^{2}+ Ax + By + C = 0In your case, it's simply

**x**^{2}+ y^{2}- 25 = 0## Still looking for help? Get the right answer, fast.

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Arturo O.

^{2}- y^{2}= 5.^{2}+ y^{2}= 5^{2}?06/30/18