graph the linear equation by solving for y first

-2x+5y=-15

+2x +2x

5y = 2x - 15

/5 /5 /5

y=2/5x -3

1st oredered pairs of y=2/5x-3 is (0,-3)

graph the linear equation by solving for y first

-2x+5y=-15

+2x +2x

5y = 2x - 15

/5 /5 /5

y=2/5x -3

1st oredered pairs of y=2/5x-3 is (0,-3)

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You worked everything out perfectly. So you have the following linear equation:

y = (2/5)x - 3

The first ordered pair you found is (0, -3), which means that when x = 0 then y = -3.

So for the next ordered pair, pick an x and plug it into the equation to solve for y.

For simplicity, let's solve for y when x = -5 and when x = 5:

x = -5

y = (2/5)(-5) - 3

y = -2 - 3

y = -5

thus, this ordered pair is **(-5, -5)**

x = 5

y = (2/5)(5) - 3

y = 2 - 3

y = -1

thus, this ordered pair is **(5, -1)**

In the formula y=mx +b, m = the slope of the line. This is how the points on the line are plotted. If you've found the first point is (0, -3) then since the slope is 2/5 2 = the movement on the y axis, and 5 = the movement on the x axis. You can either move have the next point be up 2 and over 5 to the right from (0, -3) or down 2 and back 5 from (0, -3). Therefore 2 other points that should work are (5, -1) and (-5, -5). Plug both into your equation of y = 2/5x - 3 and you will see that both points fit into the line.

Another option is to plug any number in for x OR y in order to find new points. An example would be to plug 5 in for x and solve for y: y = 2/5 (5) - 3. y= 2 - 3 and y would then equal -1.

Please e-mail me if you are still confused, have further questions, or if you know someone who may be looking for a tutor this summer in the greater DC/Baltimore area!

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