Raymond B. answered • 12/13/20

Math, microeconomics or criminal justice

v = s' = 60-32t = velocity at time t

t = 60/32 = 15/8 = 1.825 seconds = time of zero velocity = time of maximum height

t=15/8 is time when velocity = 0 and the ball is at maximum height. Plug t=15/8 into the s(t) equation to calculate that maximum height = 60(15/8) - 16(15/8)^2 = 4(15/8)[15-4(15/8)] =(15/2)(15/2) = 225/4= 56.25 meters.

(you must have a typo or misprint, as -16t^2 is the formula for gravity in feet/sec^2, not for meters. the meter deceleration is -4.9t^2

acceleration is the derivative of v = a' = -32 feet per second per second = -9.8 meters per second per second

take the antiderivative or integral of a to derive velocity. Integral of -32 = -32t + constant which is given as 60. double integral of a(t) = s(t) = 60t -16t^2 + constant which is given as zero.)