Andrew M. answered • 03/12/18

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

The area to be resurfaced is the area of the

whole circle including garden and lanes minus

the area of the garden.

Area of a circle is (pi)r

^{2}radius of garden is (1/2)diameter = 8 m

Garden area: (pi)8

^{2}= 64(pi) m^{2}^{}Diameter of garden plus traffic lanes is

16 + 2(6) because we add 6 m to both sides

of the diameter of the garden.

Full diameter = 16+12 = 28 m

Full radius = 28/2 = 14 m

Full area: (pi)14

^{2}= 196(pi) m^{2}Area to be resurfaced:

196(pi) - 64(pi) = 132(pi) m

^{2 }≅ 415 m^{2}