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A reaction of 44.3 g of Na and 52.3 g of Br2 yields 53.5 g of NaBr. What is the percent yield?

i need to find the percent yield of the above equation..

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J.R. S. | Ph.D. in Biochemistry--University Professor--Chemistry TutorPh.D. in Biochemistry--University Profes...
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Write the balanced equation:  2Na + Br2 ==> 2NaBr
Determine which reactant, if any, is limiting:
moles Na present = 44.3 g x 1 mole/23 g = 1.93 moles Na
moles Br2 present = 52.3 g x 1 mole/159.8 g = 0.327 moles Br2
Since it takes 2 moles Na for each 1 mole Br2, there is enough Na so Br2 is limiting.
Theoretical yield is based on the limiting reactant, thus theoretical yield is....
0.3273 moles Br2 x 2 moles NaBr/1 mole Br2 = 0.655 moles NaBr theoretical yield
Theoretical yield in grams = 0.655 moles NaBr x 102.9 g/mole = 67.47 g
Percent yield = 53.5 g/67.5 g (x100%) = 79.3% yield