Plane flies at 4400 feet

3200 feet terminal velocity is reached.

2500 feet parachute opens

at 3200 feet Terminal velocity is reached of -160 feet per second

Plane flies at 4400 feet

3200 feet terminal velocity is reached.

2500 feet parachute opens

at 3200 feet Terminal velocity is reached of -160 feet per second

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Orlando, FL

Katie,

Once the skydiver reaches terminal velocity, then he will be falling with constant speed. The distance he falls in time t will then be d = (160 ft/s)·t. And his altitude above the ground (height h) will be his altitude when the parachute opened minus the distance he has fallen so we can write:

h = (3200 ft) - (160 ft/s)·t

As a point of interest, the time it will take him to fall all the way to the ground is t = (3200 ft)/(160 ft/s) = 20 s

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