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Sarah G.

asked • 12/15/17

A ball is thrown downward from the top of a 130​-foot building with an initial velocity of 22 feet per second. The height of the ball h after t seconds is given

A ball is thrown downward from the top of a 130-foot building with an initial velocity of 22 feet per second. The height of the ball h after t seconds is given by the equation .h= −16t2−22t+130. How long after the ball is thrown will it strike the ground?

Andrew M.

Apparently the person throwing the ball off the building is laying down when he does so;
otherwise, the initial height should be 130 ft plus the height of the person.
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12/15/17

Mark O.

That's funny, but true. :-)
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12/15/17

2 Answers By Expert Tutors

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Mark O. answered • 12/15/17

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Andrew M. answered • 12/15/17

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Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

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