dimensions
21 feet and 82
Let w = the width
Let w + 21 = the length
P = 2l + 2w
82 = 2(w+21) + 2w
82 = 2w + 42 + 2w
40 = 4w
10 feet = w
length = w + 21 = 10 + 21 = 31 feet
what are the dimensions of a rectangle with a perimeter of 82 and the length of 21 feet longer than the width
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