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# if the perimeter of basketball court is 114 meters and the length is 6 meters longer then twice the width, what are the length and width

how to i set up the problem, and how do i work out the problem

### 1 Answer by Expert Tutors

Pierce O. | Graduate Mathematics Student, Will Tutor Any Math SubjectGraduate Mathematics Student, Will Tutor...
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Hi Brynn,

The shape of a basketball court is a rectangle, and we know that the perimiter of a rectangle is given by

2l+2w=P

where l is the length and w is the width. Since we are given P = 114, we have

2l+2w=114

If the length is 6 meters longer than twice the width, then

l=6+2w

Now, substituting this back into 2l + 2w = 114, we have

2(6+2w)+2w = 114    (substitution)

12+4w+2w    = 114    (distribution)

12+6w           = 114    (add like terms)

Now we can solve for w. Taking 12 away from both sides leaves us with

6w = 101

and dividing by 6 yields the result

w = 17

Since we know that l = 6 + 2w, we have

l = 6 + 2(17)

= 40

So the length is 40 and the width is 17.