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A rectangular wall needs 80 square feet of wallpaper. The width of the wall is 2 feet less than its length.

Help me with is problem it is difficult need some help with it. And some more random words just tho fit the chrarcters and song chi humendala he mu

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Arturo O. | Experienced Physics Teacher for Physics TutoringExperienced Physics Teacher for Physics ...
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I assume you seek the dimensions of the wallpaper.
 
A = LW
 
A = 80 ft2
 
W = L - 2  [ft]
 
80 = L(L - 2) 
 
80 = L2 - 2L
 
Solve for L.
 
L2 - 2L - 80 = 0
 
(L - 10)(L + 8) = 0
 
L = 10 or -8
 
But length must be positive, so 
 
L = 10 ft
 
W = (10 - 2) ft = 8 ft