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my quetion is.....find the value of (x-2y)^-5 if x^5+7=3132 and y^6-13=4083

i want answer of my question my quetion is.....find the value of (x-2y)^-5 if x^5+7=3132 and y^6-13=4083???????
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1 Answer

Since x5 + 7 = 3132, x5 = 3125.  So, x = 31251/5 = 5.
 
Since y- 13 = 4083, y = 4096.  So, y = 40961/6 = 4.
 
Therefore, (x - 2y) -5 = (-3)-5 = 1/(-3)5 = 1/243.  

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