Ni(CO)4 ==> Ni(s) + 4CO(g)
moles Ni(CO)4 present = 444 g x 1 mole/170.73 g = 2.60 moles
moles CO produced = 2.60 moles Ni(CO)4 x 4 moles CO/mole Ni(CO)4 = 10.40 moles CO produced.
Now, the volume of CO gas will depend on the temperature and pressure of the experiment. So, the question is actually poorly written since it does not state the conditions. Assuming it is STP (1 atm and 273K) then 1 mole = 22.4 liters and
10.40 moles x 22. 4 liters/mole = 233 liters.