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A merry-go-around completes one revolution every 21.5 s. Compute the acceleration of a child seated on it, a distance of 6.25m from its center.

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1 Answer

This is a case of centripetal acceleration, ac.
 
ac = ω2r = [2π / (21.5 s)]2 (6.25 m) ≅ 0.5338 m/s2
 
It points from the position of the child toward the center of the merry-go-round.