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5 times the greateat of three consecutive even integers is equal to twice the sum of the other two integer plus 42. What are the three integers?

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2 Answers

let the integers be n, n+2 and n+4
 
5(n+4) = 2(n + n+2) +42
 
5n +20 = 4n +4+42
 
n = 46 -20 = 26
 
The even integers are 26, 28 and 30
Hi Owen;
 
Consecutive even integers are
separated by 2
 
x = smallest
x + 2 = middle
x + 4 = largest
 
5(x+4) = 2(x+x+2) + 42
5x + 20 = 2(2x+2) + 42
5x + 20 = 4x + 4 + 42
5x + 20 = 4x + 46
 
Can you finish solving for x to find 1st integer?
Then the next are x+2 and x+4