5 times the greateat of three consecutive even integers is equal to twice the sum of the other two integer plus 42. What are the three integers?
This problem is impossible
2 Answers By Expert Tutors
Patient and Qualified Math Tutor
let the integers be n, n+2 and n+4
5(n+4) = 2(n + n+2) +42
5n +20 = 4n +4+42
n = 46 -20 = 26
The even integers are 26, 28 and 30
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Consecutive even integers are
separated by 2
x = smallest
x + 2 = middle
x + 4 = largest
5(x+4) = 2(x+x+2) + 42
5x + 20 = 2(2x+2) + 42
5x + 20 = 4x + 4 + 42
5x + 20 = 4x + 46
Can you finish solving for x to find 1st integer?
Then the next are x+2 and x+4
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