This problem is impossible Sep 18 | Owen from Narberth, PA | 2 Answers | 1 Vote Mark favorite Subscribe Comment
let the integers be n, n+2 and n+4 5(n+4) = 2(n + n+2) +42 5n +20 = 4n +4+42 n = 46 -20 = 26 The even integers are 26, 28 and 30 Sep 18 | Michael C. Comment
Hi Owen; Consecutive even integers are separated by 2 x = smallest x + 2 = middle x + 4 = largest 5(x+4) = 2(x+x+2) + 42 5x + 20 = 2(2x+2) + 42 5x + 20 = 4x + 4 + 42 5x + 20 = 4x + 46 Can you finish solving for x to find 1st integer? Then the next are x+2 and x+4 Sep 18 | Andrew M. Comment