From a boat on the lake, the angle of elevation to the top of a cliff is 30°50'. If the base of the cliff is 1038 feet from the boat, how high is the cliff(to the nearest foot)?
Say , the height of cliff is h feet.
h/1038 = tan(30 dig, 50 min)
= 619.6 feet
The height of cliff is 619.6 feet