$6300 is invested, part of it at 10% and part of it at 9%. For a certian year, the total yeild is $598.00 How much was invested at each rate? How much was invested at 10%____ How much was invested at 9%_____ Jul 7 | Shawn from Miami, FL | 1 Answer | 0 Votes Mark favorite Subscribe Comment
The equations are: x+y=6300 0.1x + 0.09Y=598 multiplying the second equation by -10 we obtain -x - 0.9y =-5980 adding equations 1 and 2 modified we have: 0.1y = 320 Y=3200 and x=6300-3200= 3100 3200X0.09+3100X0.1=598 CHECK Jul 7 | Francisco E. Best answer Comment