The slope of any line perpendicular to L must be -7/13.

The line through (6,-5) and (-7,2) has slope [2-(-5)]/(-7-6) = -7/13.

Trinity C.

asked • 07/23/17(-5,-7) (2,6)

(6,-5) (-7,2)

(-8,-7) (2,6)

(12,-3) (-7,4)

Follow
•
3

Add comment

More

Report

The slope of any line perpendicular to L must be -7/13.

The line through (6,-5) and (-7,2) has slope [2-(-5)]/(-7-6) = -7/13.

Michael A. answered • 07/23/17

Tutor

5.0
(1,434)
Top Tutor for Math/AFOQT/ASVAB/HESI/TEAS/ACCUPLACER

You need to find the set of points that will yield a slope that is the negative reciprocal of the slope of Line L because perpendicular lines have negative reciprocal slopes. The negative reciprocal of 13/7 is -7/13. Which set of points will produce this result? The formula for finding the slope is:

m = (y_{2} - y_{1})/(x_{2} - x_{1})

Consider the second set of coordinates.

(2 - (-5))/(-7 - 6) = (2 + 5)/(-13) = -7/13

The second set of coordinates satisfy the condition.

Ask a question for free

Get a free answer to a quick problem.

Most questions answered within 4 hours.

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.